what is the differences??

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Airconvent
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Post by Airconvent »

ChaosKnight wrote:
rlow wrote:Sharp optics you have, chaosknight; you are spot on. That was indeed some sloppy work I did. Next time I better open my eyes and think twice before I consider to post here.

Yes, it should have read as "...or the radius of the Earth' orbit."
Hahaaa.....well....to be fair the definition i posted abt 1 AU subtended at 1 arc sec isn't so complete either.
mm..i've always thought the earth's orbit is not circular?
that was the reason why Kepler initially could not reconcile his readings with his calculation when he was developing hisl laws on planetary motion..the orbit were elliptical?

rich
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Post by ChaosKnight »

Airconvent wrote:
ChaosKnight wrote:
rlow wrote:Sharp optics you have, chaosknight; you are spot on. That was indeed some sloppy work I did. Next time I better open my eyes and think twice before I consider to post here.

Yes, it should have read as "...or the radius of the Earth' orbit."
Hahaaa.....well....to be fair the definition i posted abt 1 AU subtended at 1 arc sec isn't so complete either.
mm..i've always thought the earth's orbit is not circular?
that was the reason why Kepler initially could not reconcile his readings with his calculation when he was developing hisl laws on planetary motion..the orbit were elliptical?


rich
Yes. But since the Earth's orbital ellipse has very low eccentricity, 1AU is loosely taken as the radius of the orbital path. If i remember correctly, the exact definition of 1AU is the semi-major axis of the Earth's orbital path.
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zong
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Post by zong »

Haha.. actually, in numbers.. Earth's orbit eccentricity is 0.98, with 1 being a perfect circle and 0 being super eccentric. So you might wanna safely assume the semi-major and minor axes of Earth's orbit to be the same.. oops, i think getting quite off-topic here..

Anyway back to it, I suppose we had better just remember 1 parsec=3.26 light years, it's all the better than arguing the definition of a parsec, eh :lol: So, putting the star a parsec away from us, that's the real magnitude (take not not apparent) of the star. That's the definition of real magnitude, don't ask why they used one parsec as the standard. They just did. :P
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Post by ChaosKnight »

zong wrote:Haha.. actually, in numbers.. Earth's orbit eccentricity is 0.98, with 1 being a perfect circle and 0 being super eccentric. So you might wanna safely assume the semi-major and minor axes of Earth's orbit to be the same.. oops, i think getting quite off-topic here..

Anyway back to it, I suppose we had better just remember 1 parsec=3.26 light years, it's all the better than arguing the definition of a parsec, eh :lol: So, putting the star a parsec away from us, that's the real magnitude (take not not apparent) of the star. That's the definition of real magnitude, don't ask why they used one parsec as the standard. They just did. :P
Real magnitude = absolute magnitude?
Is the standard 1 parsec? :D
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weixing
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Post by weixing »

Hi,
It should be 10 parsec (36.2 light year).

Have a nice day.
Yang Weixing
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Airconvent
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Post by Airconvent »

weixing wrote:Hi,
It should be 10 parsec (36.2 light year).

Have a nice day.

mmm...weixing...what should be 10 parsecs?

Have a nice night (more impt! )

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weixing
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Post by weixing »

Hi,
Absolute magnitude is the apparent magnitude the star would have if it were placed at a distance of 10 parsecs(36.2 light year) from Earth.

Too cloudy to have a nice night... :P Anyway, hope that chinese new year eve will be a clear night...

Have a nice day.
Yang Weixing
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Post by zong »

Oops, sorry for wrong info about the distance set for real magnitude.. :oops: guess i have too much school stuff cramped into my brains already..

I see quite some people confused about apparent and real magnitude.

Imagine a bright source very near (1m) to you. Is it very very bright? Now bring it 10m from you. It should look dimmer now right?
Vice versa, let's imagine a very dim object 100m away. It looks real dim. But if you bring it to 10m from you, it looks brighter!

Scientists therefore have to put a standard on how to measure brightness. They set the distance to 10 parsecs, ie 32.6 light years, for the measurement of brightness. Therefore, to measure the real magnitude of any body, you have to put it 10 parsecs away from you. This is the real comparison of brightness of the different bodies.

However, for apparent magnitude, it just measures the brightness WITHOUT taking into account distance. This means, although the sun is dimmer than Sirius, it registers a lower magnitude (ie. brighter) than Sirius. Please take note that apparent and real magnitudes are really different.

However, I have read a formula somewhere that relates these two. I have forgotten it, maybe someone else could enlighten us? ;)
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Post by weixing »

Hi,
The formula of Absolute Magnitude(M):
M = m + 5 - 5 log d

m: Apparent Magnitude
d: Distance in Parsec

Have a nice day.
Yang Weixing
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